Network Analysis: Minimum Spanning Tree,

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Network Analysis: Minimum Spanning Tree, M. en C. Eduardo Bustos Farías 1

Definitions A network consists of a set of nodes and a set of arcs connecting the nodes Nodes are also called vertices or points Arcsare also called edges, links, lines, or orilla branches A network is also called a graph in mathematics M. en C. Eduardo Bustos Farías 2

Graphs A graph is represented by the notation: G = ( N, A), where, N and, A the set of the set of nodes arcs in graph G M. en C. Eduardo Bustos Farías 3

Arcs An arc is undirected if it does not have a specific orientation It is directed if it has exactly one orientation It is bidirected if it has two orientations M. en C. Eduardo Bustos Farías 4

Conventions Circles are used to represent nodes Lines are used to indicate arcs Arrowheads are used to indicate orientation in a network i j Directed Arc i j Undirected Arc i j Bidirected Arc M. en C. Eduardo Bustos Farías 5

Conventions Arcs are represented by the ordered twotuples of the nodes at its endpoints, e.g., (i,j) or (j,i) The order of the two-tuples indicates direction of flow through the arc, e.g., (i,j) implies flow from node i to node j along arc (i,j) M. en C. Eduardo Bustos Farías 6

Paths When two nodes are not connected by a single arc, there may be a path between the two nodes through the network A pathis a sequence of distinct arcs connecting two nodes of a network M. en C. Eduardo Bustos Farías 7

Paths A directed path from node i to node j is sequence of connecting arcs whose direction, if any, is toward node j An undirected path from node i to node j is a sequence of connecting arcs whose direction, if any, can be either toward or away from node j M. en C. Eduardo Bustos Farías 8

Cycles A path that begins and ends on the same node is a cycle In a directed network, a cycle is either a directed cycle or an undirected cycle, depending upon whether the path involved is a directed or undirected path M. en C. Eduardo Bustos Farías 9

Connectedness Two nodes are said to be connected if the network contains at least one undirected path between them Note, the path does not need to be directed even if the network is directed igual A connected network (or connected graph) is one where every pair of nodes is connected M. en C. Eduardo Bustos Farías 10

Trees If G=(N,A), we may define a subset of G as G = ( N, A A treeis defined as a connecting subset containing no undirected cycles A spanning tree is a connected network for all N nodes which contains no undirected cycles ) G M. en C. Eduardo Bustos Farías 11

Spanning Trees Every spanning tree has exactly (N-1) arcs This is the minimum number of arcs needed to have a connected network, and the maximum number possible without having undirected cycles M. en C. Eduardo Bustos Farías 12

Arc Capacity and Node Types Arc capacity = maximum amount of flow that can be carried on directed arc A supply node (or source node) has the property that flow out > flow into the node A demand node (or sink) has the property that flow into the node > flow out of the node A transshipment node (or intermediate node) transbordo satisfies conservation of flow, i.e., flow in = flow out M. en C. Eduardo Bustos Farías 13

Dijkstra s Algorithm (Undirected Arcs) Objective of the n th iteration: Find the n th nearest node to the source (repeat for n=1, 2,..., until the n th nearest node is the sink) Input for n th iteration: (n-1) nearest nodes to the source (found in previous iterations), including their shortest path and distance from the source. These nodes, plus the origin, are called solved nodes, the others are unsolved nodes. M. en C. Eduardo Bustos Farías

Dijkstra s Algorithm (Undirected Arcs) Candidates for n th nearest node: Each solved node directly connected by an arc to one or more unsolved nodes provides one candidate -- the unsolved node with the shortest connecting link (ties provide additional candidates) M. en C. Eduardo Bustos Farías 15

Dijkstra s Algorithm (Undirected Arcs) Calculation of the n th nearest node: For each such solved node and its candidate, add the distance between them and the distance of the shortest path form the source to this solved node. The candidate with the smallest such total distance is the n th nearest node (ties provide additional solved nodes), and its shortest path is the one generating this distance M. en C. Eduardo Bustos Farías 16

Minimum Spanning Tree This problem involves choosing for the network the links that have the shortest total length while providing a path between each pair of nodes These links must be chosen so that the resulting network forms a tree that spans all abarca the given nodes of the network, i.e., a spanning tree with minimum total length of the links M. en C. Eduardo Bustos Farías 17

MST Algorithm 1. Start with any node and join it to its closest node in the network. The resulting two nodes now form a connected set, and the remaining nodes comprise the unconnected set 2. Choose a node from the unconnected set that is closest to any node in the connected set and add it to the connected set M. en C. Eduardo Bustos Farías 18

MST Algorithm 3. Redefine the connected and unconnected sets accordingly. Repeat the process until the connected set includes all the nodes in the network 4. Ties may be broken arbitrarily; however, empates ties indicate the existence of alternative minimal spanning trees! M. en C. Eduardo Bustos Farías 19

Example 1 2 6 3 5 1 9 3 8 7 4 5 10 4 3 6 Beginning with node 1, compute a MST for this network M. en C. Eduardo Bustos Farías 20

Example Let c = the set of connected nodes at any iteration c = the set of unconnected nodes at any iteration Iteration # c c 1 {1} {2,3,4,5,6} 1 M. en C. Eduardo Bustos Farías 21

Example Let c = the set of connected nodes at any iteration c = the set of unconnected nodes at any iteration Iteration # c c 1 {1} {2,3,4,5,6} 2 {1,2} {3,4,5,6} 1 1 1 2 M. en C. Eduardo Bustos Farías 22

Example Let c = the set of connected nodes at any iteration c = the set of unconnected nodes at any iteration Iteration # c c 1 {1} {2,3,4,5,6} 2 {1,2} {3,4,5,6} 3 {1,2,5} {3,4,6} 1 1 1 1 2 1 2 3 5 M. en C. Eduardo Bustos Farías 23

Example Let c = the set of connected nodes at any iteration c = the set of unconnected nodes at any iteration Iteration # c c 1 {1} {2,3,4,5,6} 2 {1,2} {3,4,5,6} 3 {1,2,5} {3,4,6} 4 {1,2,4,5} {3,6} 1 1 1 1 1 1 1 2 2 2 3 3 5 5 4 M. en C. Eduardo Bustos Farías 24 4

Example 1 1 2 3 4 5 Iteration # c c 1 {1} {2,3,4,5,6} 2 {1,2} {3,4,5,6} 3 {1,2,5} {3,4,6} 4 {1,2,4,5} {3,6} 5 {1,2,4,5,6} {3} 4 3 6 M. en C. Eduardo Bustos Farías 25

Example 1 2 3 1 4 4 Minimal Spanning Tree Min. Total Distance = 16 3 1 5 6 1 4 Iteration # c c 1 {1} {2,3,4,5,6} 2 {1,2} {3,4,5,6} 3 {1,2,5} {3,4,6} 4 {1,2,4,5} {3,6} 5 {1,2,4,5,6} {3} 6 {1,2,3,4,5,6} { } 2 4 5 3 3 3 5 6 M. en C. Eduardo Bustos Farías 26

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Kruskal s algorithm Edge first 1. Arrange all edges in a list (L) arcos in non-decreasing order 2. Select edges from L, and include that in set T, avoid cycle. 3. Repeat 3 until T becomes a tree that covers all vertices M. en C. Eduardo Bustos Farías 35

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 36

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 37

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 38

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 39

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 40

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 41

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 42

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 Skip {7,8} to avoid cycle {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 Skip M. en C. Eduardo Bustos Farías 43

Kruskal s Algorithm {1,2} 12 15 {3,4} 12 {1,8} 13 13 13 {4,5} 13 16 1 4 {2,7} 12 12 {3,6} 2 {7,8} Skip 3 16 {5,6} Skip {5,8} 15 8 5 7 6 15 Skip {5,6} to avoid cycle {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 44

Kruskal s Algorithm 8 5 13 13 16 12 15 1 4 2 3 16 7 6 15 12 MST is formed {1,2} 12 {3,4} 12 {1,8} 13 {4,5} 13 {2,7} {3,6} {7,8} {5,6} {5,8} 15 {6,7} 15 {1,4} 16 {2,3} 16 M. en C. Eduardo Bustos Farías 45

Prim s algorithm Start form any arbitrary vertex Find the edge that has minimum weight form all known vertices Stop when the tree covers all vertices M. en C. Eduardo Bustos Farías 46

Prim s algorithm 8 5 13 13 16 1 4 12 12 15 2 3 16 7 6 15 Start from any arbitrary vertex 1 M. en C. Eduardo Bustos Farías 47

Prim s algorithm 8 5 13 13 16 1 4 12 15 2 3 16 7 6 15 12 1 The best choice is {1,2} 2 Weight:12 What s next? M. en C. Eduardo Bustos Farías 48

Prim s algorithm 8 5 1 4 12 15 16 2 3 16 13 7 6 15 8 13 12 1 2 Weight:12+13 After {1,8} we may choose {2,7} or {7,8} There are more than one MST What s next? M. en C. Eduardo Bustos Farías 49

Prim s algorithm 15 8 5 16 1 4 12 2 3 16 13 7 6 15 8 7 13 12 1 2 Let s choose {2, 7} at this moment We are free to choose {5,8} or {6,7} but not {7,8} because we need to avoid cycle M. en C. Eduardo Bustos Farías 50

Prim s algorithm 8 5 16 1 4 12 2 3 16 13 7 6 15 8 7 13 12 1 2 15 5 Let s choose {5,8} at this moment The best choice is now {4,5} M. en C. Eduardo Bustos Farías 51

Prim s algorithm 8 5 16 1 4 12 2 3 16 7 6 15 8 7 13 12 1 2 15 4 13 5 The best choice is now {4,3} M. en C. Eduardo Bustos Farías 52

Prim s algorithm 8 5 16 1 4 2 3 16 7 6 15 8 7 13 12 1 2 15 4 3 13 12 5 The best choice is now {3,6} or {5,6} M. en C. Eduardo Bustos Farías 53

Prim s algorithm 8 5 16 1 4 2 3 16 8 13 12 1 2 15 4 3 13 12 5 A MST is formed Weight = 93 7 6 15 7 6 M. en C. Eduardo Bustos Farías 54

Prim s algorithm more complex 3 20 44 54 0 8 5 100 99 32 11 31 19 M. en C. Eduardo Bustos Farías 55

Prim s algorithm more complex 3 20 44 54 0 8 5 100 99 32 11 31 19 M. en C. Eduardo Bustos Farías 56

Prim s algorithm 3 20 44 54 0 8 5 100 99 32 11 31 19 M. en C. Eduardo Bustos Farías 57

Prim s algorithm 3 20 44 54 0 8 5 100 99 32 11 31 19 M. en C. Eduardo Bustos Farías 58

Prim s algorithm 3 20 44 54 0 8 5 100 99 32 11 31 19 M. en C. Eduardo Bustos Farías 59

Prim s algorithm 3 20 44 54 0 8 5 100 99 32 11 31 19 M. en C. Eduardo Bustos Farías 60

Prim s algorithm 3 20 44 54 0 8 5 100 99 32 11 31 19 M. en C. Eduardo Bustos Farías 61

Prim s algorithm 3 20 44 54 0 8 5 100 99 32 11 31 19 M. en C. Eduardo Bustos Farías 62

Prim s algorithm 3 20 44 54 0 8 5 100 MST is formed 99 32 11 31 19 M. en C. Eduardo Bustos Farías 63

Compare Prim and Kruskal Both have the same output MST Kruskal s begins with forest and merge into a tree Prim s always stays as a tree If you don t know all the weight on edges use Prim s algorithm If you only need partial solution on the graph use Prim s algorithm M. en C. Eduardo Bustos Farías 64

Why do we need MST? A reasonable way for clustering points in space into natural groups Can be used to give approximate solutions to hard problems M. en C. Eduardo Bustos Farías 65

Minimizing costs Suppose you want to provide solution to : electric power, Water, telephone lines, network setup To minimize cost, you could connect locations using MST However, MST is not necessary the shortest path and it does not apply to cycle M. en C. Eduardo Bustos Farías 66

Example Find the shortest path through the following network from O to T 2 A 2 7 O 5 B 4 D 5 T 4 1 3 1 7 C 4 E M. en C. Eduardo Bustos Farías 67

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Ejemplo 1 Se va a instalar una red de comunicación entre 12 ciudades. Los costos de los posibles enlaces directos entre pares permisibles es el que se muestra en la figura. Cada unidad de costo representa $10,000 dólares. M. en C. Eduardo Bustos Farías 74

1 4 2 6 3 6 4 1 3 7 1 5 4 6 5 7 2 8 9 7 2 2 9 5 10 3 11 1 12 M. en C. Eduardo Bustos Farías 75

SOLUCIÓN CON WINQSB M. en C. Eduardo Bustos Farías 76

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Solución Interacción Nodo Con nodo Costo ($) 1 1 5 1 2 1 2 4 3 2 6 3 4 6 7 5 5 7 8 2 6 8 4 1 7 7 11 2 8 11 12 1 9 11 10 3 10 10 9 5 11 2 3 6 SUMA $33 M. en C. Eduardo Bustos Farías 91

Método Tabular 1 2 3 4 5 6 7 8 9 10 11 12 1 4 1 2 4 6 3 3 6 6 7 4 6 1 5 1 4 9 6 3 4 5 7 7 7 5 2 2 8 1 2 2 9 9 5 10 7 5 3 11 2 3 1 12 2 1 M. en C. Eduardo Bustos Farías 92